Final answer:
When a 1cm stand off pad is added, the focal point is altered, moving the lens closer or further from the object, which can affect magnification. However, the exact impact on elevation focus or magnification depends on specific details of the lens system which are not provided.
Step-by-step explanation:
The question appears to be related to the physics of lenses and how adjustments to the position of an optical system can affect the focal point. A stand off pad of 1cm thickness alters the distance between the lens and the object. In an optical setup such as a microscope or telescope, when you move the lens closer to or further from the object, it affects where the elevation focus is located, which is the point where light rays converge to form a clear image. Typically, moving the objective lens closer to the object could increase magnification, assuming that we are talking about a simple maginification setup where the object distance is much less than the focal length of the lens. However, without specific details about the lens system, one cannot deduce the exact effect on the elevation focus or magnification.
In the context of an eye, the setup described in the equation you provided (16 cm image-side focal point distance, 25 cm near point distance, fobj and feye being the focal distances) suggests a basic optical system. The situation where an objective lens is moved from 6 mm to 7 mm from the object can have a varying impact on magnification based on the type of lens system in use. As for the example given regarding the image of a tree on the retina, using similar triangles and proportionality, the height of the image can be found by setting up a ratio of the tree's height to its distance from the eye and the image's height to the cornea-to-retina distance.