Question

For the function f(x)=(x ² −13x+40)(x ² −2x−3),what is the y-coordinate of the y-intercept, located at the point (0, _)?

A) 40
B) 120
C) -120
D) -40

Answer 1

The y-coordinate of the y-intercept for the function f(x)=(x² −13x+40)(x² −2x−3) is found by substituting x=0, yielding -120. So the correct answer is C) -120.

Step-by-step explanation:

The student is asking for the y-coordinate of the y-intercept of the function f(x)=(x² −13x+40)(x² −2x−3). To find the y-intercept, we substitute x=0 into the function. Doing this, we get:

f(0) = (0² −13×0+40)(0² −2×0−3)

f(0) = (40)(−3)

f(0) = −120

Thus, the y-coordinate of the y-intercept is −120, making the correct answer C) -120.