Final answer:
To find the distance traveled during the 10th second under uniform acceleration, we can use the formula relating distance, initial velocity, and acceleration. Given the distances traveled in the 3rd and 8th seconds, we can solve for initial velocity and acceleration, and then apply those values to the formula for the 10th second.
Step-by-step explanation:
The student's question seems to contain a typo, but it appears they are asking about uniform acceleration and distance traveled during specific seconds. I will show you how to determine the distance traveled during a particular second when an object undergoes uniform acceleration.
For this, we use the formula for the distance covered during the n-th second, which is s_n = u + a/2 (2n - 1), where s_n is the distance traveled during the n-th second, u is the initial velocity, a is the acceleration, and n is the second in question.
To find the distance traveled during the 10th second, we will first need to determine the initial velocity and acceleration from the given distances in the 3rd and 8th seconds. For consistency, let's begin by correcting the 'min' in the question to 'm' for meters, assuming min was a typo.
Now, let's assume the initial velocity is u and acceleration is a. From the 3rd second distance, we get u + a/2 (2*3 - 1) = 15 m, and from the 8th second, we get u + a/2 (2*8 - 1) = 25 m. By solving these two equations simultaneously, we can find u and a, then substitute those into the formula for the 10th second: u + a/2 (2*10 - 1) to find the distance traveled in the 10th second.