Question

Consider a B+ tree in which the search key is 12 bytes long, lock size is 102bytes, record pointer is 10bytes long and block pointer is 8bytes long. The maximum number of keys that can be accomplished in each non-leaf code of the tree is____

Answer 1

To calculate the maximum number of keys in a non-leaf node of a B+ tree, one must account for the sizes of search keys, record pointers, and block pointers.

Step-by-step explanation:

The question pertains to the B+ tree data structure, which is a type of self-balancing tree structure that maintains sorted data in a way that allows for efficient insertion and deletion operations. To find the maximum number of keys that can fit in each non-leaf node of the B+ tree, we have to consider the size of the search keys, record pointers, and block pointers.

Each non-leaf node consists of keys and block pointers to the child nodes. For n keys, there will be n+1 pointers. The formula to calculate the maximum number of keys in each non-leaf node is:

Block Size = (Key Size + Block Pointer) * Number of Keys + Block Pointer

Substituting the given values:

102 = (12 + 8) * Number of Keys + 8

Solving for the number of keys, we get:

Number of Keys = (102 - 8) / (12 + 8) = 94 / 20 = 4.7

Since the number of keys must be a whole number, the maximum number of keys that can fit is 4.