Question

The school yard is twice as long as it is wide. The width is 23 yards. How much fencing is needed to enclose the school yard?

Answer 1

Explanation:

P=2(L+W) and we are told L=2W so

P=2(2W+W)

P=2(3W)

P=6W and we are told W=23 yd so

P=6(23)

P=138 yd

Answer 2

138ft

Explanation:

w = 23, h = 46

23 × 2 = 46

23 + 23 + 46 + 46 = 138

138ft is needed

good luck, hope this helps :)