Question

The spinner below is spun twice. If the spinner lands on a border, that spin does not count and spin again.

It is equally likely that the spinner will land in each of the six sectors.
RED
BLUE
BLUE
RED
RED
CYAN
57
Q
For each question below, enter your response as a reduced fraction.
Find the probability of spinning red on the first spin and cyan on the second spin.
P(red and cyan) =
Find the probability of spinning red on the first spin and blue on the second spin.
P(red and blue) =
Find the probability of NOT spinning blue on either spin. (Not blue on the first spin and not blue on the
second spin.)
P(not blue and not blue)=

Answer 1

The probability of spinning red on the first spin and cyan on the second spin { P(red and cyan) = 1/9.

The probability of spinning red on the first spin and blue on the second spin { P(red and blue) = 1/9.

The probability of not spinning blue on either spin [ P(not blue and not blue) ] is 8/9.

Step-by-step explanation:

To find the probability of spinning red on the first spin and cyan on the second spin, we need to multiply the individual probabilities of each event.

The probability of spinning red on the first spin is 2/6, or 1/3. And since the spinner is spun twice, the probability of spinning cyan on the second spin is also 2/6, or 1/3.

Therefore, the probability of both events occurring is (1/3) * (1/3) = 1/9.

To find the probability of spinning red on the first spin and blue on the second spin, we again multiply the individual probabilities.

The probability of spinning red on the first spin is 1/3. And since blue appears twice on the spinner, the probability of spinning blue on the second spin is 2/6, or 1/3.

Therefore, the probability of both events occurring is (1/3) * (1/3) = 1/9.

To find the probability of NOT spinning blue on either spin, we need to find the complement of spinning blue. The probability of spinning blue on the first spin is 2/6, or 1/3.

And again, since blue appears twice on the spinner, the probability of spinning blue on the second spin is 1/3.

Therefore, the probability of not spinning blue on either spin is 1 - (1/3) * (1/3)

= 1 - 1/9

= 8/9.