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if a magnitude of frequency of simple pendulum on Earth surface was(0.263Hz) What is the period for this pendulum at the same place on Earth surface?
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if a magnitude of frequency of simple pendulum on Earth surface was(0.263Hz) What is the period for this pendulum at the same place on Earth surface?

User Nanachan
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25 votes

Answer:

The period of a simple pendulum is the time it takes for the pendulum to complete one full swing. This is equal to the reciprocal of the frequency, which means that if the frequency of a simple pendulum is 0.263 Hz, its period would be 1/0.263 = 3.80 seconds. This is the time it would take for the pendulum to swing back and forth once at the same location on the Earth's surface.

Step-by-step explanation:

User Geekarist
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