Register
if a magnitude of frequency of simple pendulum on Earth surface was(0.263Hz) What is the period for this pendulum at the same place on Earth surface?
400,776 views
22 votes
22 votes
if a magnitude of frequency of simple pendulum on Earth surface was(0.263Hz) What is the period for this pendulum at the same place on Earth surface?

User Nanachan
by
2.8k points

1 Answer

25 votes
25 votes

Answer:

The period of a simple pendulum is the time it takes for the pendulum to complete one full swing. This is equal to the reciprocal of the frequency, which means that if the frequency of a simple pendulum is 0.263 Hz, its period would be 1/0.263 = 3.80 seconds. This is the time it would take for the pendulum to swing back and forth once at the same location on the Earth's surface.

Step-by-step explanation:

User Geekarist
by
3.1k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers

Other Questions

Determjne the density of liquid whose relative density is 1.25 given that the density is 1000kgm-3​
If a constant fotce of 490 newtons is applied to an object and it proceeds to accelerate in the opposjte direction at 9.8 meters per second, every second, what is its mass?
How can I solve the following? In (Figure 1), let V = 15.0 V and C1=C2=C3= 24.2 μF. Part A: How much energy is stored in the capacitor network as shown in (Figure 1)? Part B: How much energy would be stored
1. if i start with 48 ml of water in a graduated cylinder, after submerging an object the water level rises to 63 ml, what is the volume of the object. 2. if i start with 36 ml of water in a graduated
a dog is running around chasing his tail using a force of 30N. The dog has a mass of 5 kg. what is the dogs acceleration?
Link Copied!