Question

A vertical tube of radius 1 cm, open at the top to the atmosphere, contains 2 cm of oil (Densityoil = 0:82 Densitywater) sitting on 3 cm of water. What is the gauge pressure (pressure in excess of atmospheric) at the bottom?

Answer 1

The gauge pressure at the bottom is 0.82 times the gauge pressure due to the water column.

Step-by-step explanation:

To calculate the gauge pressure at the bottom of the vertical tube, we need to consider the pressure due to the weight of the fluid above it.

The gauge pressure is given by the equation: P = Patm + ρgh, where Patm is the atmospheric pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid column.

In this case, the gauge pressure at the bottom is equivalent to the pressure due to the oil column plus the pressure due to the water column.

The gauge pressure at the bottom is 0.82 times the gauge pressure due to the water column.

Therefore, the gauge pressure at the bottom is 0.82 * ρwater * g * h, where h is the total height of the water + oil column.