78.3k views
2 votes
Find the integral
(ii) √x (a² + x²)^3/2 dx​

User SilentICE
by
7.9k points

1 Answer

6 votes

Final answer:

To find the integral ∫√x (a² + x²)^(3/2) dx, we can use a substitution method. Let's substitute a² + x² = u. Then, differentiate both sides with respect to x. Rearrange the equation to solve for dx. Now, substitute the values of u and dx into the integral.

Step-by-step explanation:

To find the integral ∫√x (a² + x²)^(3/2) dx, we can use a substitution method. Let's substitute a² + x² = u. Then, differentiate both sides with respect to x:

2x dx = du

Rearrange the equation to solve for dx:

dx = (1/2x) du

Now, substitute the values of u and dx into the integral:

∫√x (a² + x²)^(3/2) dx = ∫√x u^(3/2) (1/2x) du

Simplify the expression:

∫√x (a² + x²)^(3/2) dx = (1/2) ∫u^(3/2) du

Integrate u^(3/2) using the power rule:

∫u^(3/2) du = (2/5) u^(5/2)

Substitute the value of u back into the equation:

(1/2) ∫u^(3/2) du = (1/2) (2/5) (a² + x²)^(5/2) + C

Therefore, the integral of √x (a² + x²)^(3/2) dx is (1/5) (a² + x²)^(5/2) + C, where C is the constant of integration.

User Dan Carlson
by
8.2k points

Related questions

asked Feb 27, 2024 234k views
Venkat Kotra asked Feb 27, 2024
by Venkat Kotra
9.1k points
1 answer
4 votes
234k views
asked Dec 8, 2024 214k views
Pratik Sodha asked Dec 8, 2024
by Pratik Sodha
8.0k points
1 answer
0 votes
214k views
1 answer
2 votes
65.1k views