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Cu + HNO3 --> Cu(NO3)2 + NO + H2O
how to balance... WILL GIVE 15 POINTS

User Itenyh
by
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2 Answers

9 votes

Answer:

Step-by-step explanation:

3Cu + 2HNO3 --> 3Cu(NO3)2 + 2NO + 2H2O

User Margusholland
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3.3k points
5 votes

Answer:

3 Cu + 8 HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O

Step-by-step explanation:

Make sure both sides are equal

3 Cu + 8 HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O

// start by those elements that change their oxidation degree

Cu and N

// also you can write reduction-oxidation reactions


Cu^(0) + 2
e^(-) -->
Cu^(-2) | 2


N^(+5) - 3
e^(-) -->
N^(+2) | 3

// write the numbers of electrons that are lost/gained as the coefficients of the opposite elements

// then check if H and O are the same on both sides

// adjust if they aren't.

User Kambi
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3.6k points