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In ΔAMN, ∠A = 90°, ∠N = 39°, and MN = 3 feet. Find the length of NO to the nearest tenth of a foot.

a. 2.4 feet
b. 2.8 feet
c. 3.6 feet
d. 4.2 feet

User Jrupe
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1 Answer

5 votes

Final answer:

To solve the trigonometry problem, the cosine of angle N is multiplied by the hypotenuse MN to find the length of NO. The result, rounded to the nearest tenth, is approximately 2.3 feet. There might be a typographical error in the answer choices provided.

Step-by-step explanation:

The subject of the question is Mathematics, and it appears to be of a High School grade level, as it deals with basic trigonometry in a right triangle. To find the length of segment NO in ∆AMN, where ∠A is 90° and ∠N is 39°, we can use trigonometric functions. Given that MN is the hypotenuse in this scenario and since ∠N is the angle adjacent to segment NO, we can use the cosine function which is defined as adjacent/hypotenuse.

Using this information:

  1. Find the cosine of ∠N, which is cos(39°).
  2. Multiply the length of the hypotenuse (MN) by cos(39°) to find the length of NO.

To find cos(39°), it would likely require a calculator. Let's presume the calculation yields a result of approximately 0.77. Then, the length of NO = MN × cos(39°) = 3 ft × 0.77 = 2.31 feet. Rounded to the nearest tenth of a foot, we get 2.3 feet.

However, because this answer isn't explicitly one of the listed choices, there could be a typographical error in the question or the choices provided. Based on the standard approach to such a trigonometry problem, answer (a) seems to be the closest match despite the minor difference in the value presented.

User Nibbana
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8.6k points
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