Final answer:
The ball rises 41.6 meters above the level where it leaves your hand. It takes 2.96 seconds to reach its highest point. It also takes 2.96 seconds for the ball to return to the level where it left your hand after it reaches its highest point.
Step-by-step explanation:
To determine how high the ball rises above the level where it leaves your hand, we need to calculate the maximum height the ball reaches. We can use the kinematic equation for vertical motion: R = V02 / (2g), where R is the maximum height, V0 is the initial velocity, and g is the acceleration due to gravity. Plugging in the values, we get R = (29.0 m/s)2 / (2 * 9.8 m/s2) = 41.6 m. Therefore, the ball rises 41.6 meters above the level where it leaves your hand.
To determine how long it takes for the ball to reach its highest point, we can use the kinematic equation for vertical motion: V = V0 - gt, where V is the final velocity, V0 is the initial velocity, g is the acceleration due to gravity, and t is the time. At the highest point, the final velocity is 0 m/s, so we can rearrange the equation to solve for t: t = V0 / g. Plugging in the values, we get t = 29.0 m/s / 9.8 m/s2 = 2.96 s. Therefore, it takes 2.96 seconds for the ball to reach its highest point.
To determine how long it takes for the ball to return to the level where it left your hand after it reaches its highest point, we can use the same equation: t = V0 / g. Plugging in the initial velocity and acceleration due to gravity, we get t = 29.0 m/s / 9.8 m/s2 = 2.96 s. Therefore, it takes 2.96 seconds for the ball to return to the level where it left your hand after it reaches its highest point.