50.8k views
4 votes
Two long, parallel transmission lines, 38.0 cm apart, carry 28.0-A and 77.0-A currents.

a) True

b) False

1 Answer

1 vote

Final answer:

The magnetic field between two long, parallel wires carrying currents in the same direction can be calculated using Ampere's Law and the formula = μ0 I1 I2 / (2π d). By plugging in the values given in the question, we find that the magnetic field is 1.53 x 10^-4 T, which is greater than 0. Hence the statement is True

Step-by-step explanation:

According to Ampere's Law, the magnetic field between two long, parallel wires carrying currents in the same direction is given by:

= μ0 I1 I2 / (2π d)

where:
is the magnetic field
μ0 is the permeability of free space (4π x 10-7 T m/A)
I1 and I2 are the currents flowing through the wires
d is the distance between the wires

In the given question, the currents flowing through the wires are 28.0 A and 77.0 A, and the distance between the wires is 38.0 cm (0.38 m). Therefore, we can calculate the magnetic field using the formula:

= (4π x 10-7 T m/A) x (28.0 A) x (77.0 A) / (2π x 0.38 m)

Simplifying the expression, we get:

= 1.53 x 10-4 T

Therefore, the answer is True.

User Tez Wingfield
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.