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Two long, parallel transmission lines, 38.0 cm apart, carry 28.0-A and 77.0-A currents.

a) True

b) False

1 Answer

1 vote

Final answer:

The magnetic field between two long, parallel wires carrying currents in the same direction can be calculated using Ampere's Law and the formula = μ0 I1 I2 / (2π d). By plugging in the values given in the question, we find that the magnetic field is 1.53 x 10^-4 T, which is greater than 0. Hence the statement is True

Step-by-step explanation:

According to Ampere's Law, the magnetic field between two long, parallel wires carrying currents in the same direction is given by:

= μ0 I1 I2 / (2π d)

where:
is the magnetic field
μ0 is the permeability of free space (4π x 10-7 T m/A)
I1 and I2 are the currents flowing through the wires
d is the distance between the wires

In the given question, the currents flowing through the wires are 28.0 A and 77.0 A, and the distance between the wires is 38.0 cm (0.38 m). Therefore, we can calculate the magnetic field using the formula:

= (4π x 10-7 T m/A) x (28.0 A) x (77.0 A) / (2π x 0.38 m)

Simplifying the expression, we get:

= 1.53 x 10-4 T

Therefore, the answer is True.

User Tez Wingfield
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