Question

The velocity of a diver just before hitting the water is -7.7 m/s, where the minus sign indicates that her motion is directly downward. What is her displacement during the last 0.82 seconds of the dive?

Answer 1

The displacement of the diver during the last 0.82 seconds of the dive is -6.31 meters.

Step-by-step explanation:

The displacement of the diver during the last 0.82 seconds of the dive can be calculated using the equation:

Displacement = Initial Velocity * Time + (1/2) * Acceleration * Time^2

Since the diver's motion is directly downward, the acceleration due to gravity is -9.8 m/s^2. Plugging in the values:

Displacement = (-7.7 m/s) * (0.82 s) + (1/2) * (-9.8 m/s^2) * (0.82 s)^2

Simplifying the equation, we get:

Displacement = -6.31 m

Therefore, the diver's displacement during the last 0.82 seconds of the dive is -6.31 meters.