Question

G(n)=25-49(n-1) Complete the recursive formula of g(n).

a) g(1)=25,g(n)=g(n-1)-49
b) g(1)=25,g(n)=g(n-1)+49
c) g(1)=74,g(n)=g(n-1)-49
d) g(1)=74,g(n)=g(n-1)+49

Answer 1

The correct recursive formula for g(n) is g(1)=25,g(n)=g(n-1)-49.

Step-by-step explanation:

The correct recursive formula for g(n) is option a) g(1)=25,g(n)=g(n-1)-49.

Step 1: Plug in the values from the given formula g(n)=25-49(n-1). We have g(1) = 25 - 49(1-1) = 25.

Step 2: For the recursive formula, we need to express g(n) in terms of g(n-1). Using the given formula, we get

g(n) = 25 - 49(n-1).

To express g(n) in terms of g(n-1), we subtract 49 from g(n-1).

Therefore, the recursive formula is g(n) = g(n-1) - 49

Step 3: Since we know that g(1) = 25 from the given formula, we can conclude that the correct recursive formula is

g(1) = 25 and g(n) = g(n-1) - 49.