Question

ChCl₃ + Cl₂ = CCl₄ + HCl. Determine the rate law.

A) Rate = k[ChCl₃][Cl₂]
B) Rate = k[CCl₄][HCl]
C) Rate = k[ChCl₃][Cl₂]/[HCl]
D) Rate = k[HCl]/[ChCl₃]

Answer 1

The rate law for the reaction ChCl₃ + Cl₂ = CCl₄ + HCl is Rate = k[ChCl₃][Cl₂].

Step-by-step explanation:

The rate law for the reaction ChCl₃ + Cl₂ = CCl₄ + HCl is Option A) Rate = k[ChCl₃][Cl₂].

This can be determined by comparing different experiments and analyzing how changes in concentration affect the reaction rate. In this case, it is observed that doubling the concentration of ChCl₃ doubles the reaction rate, indicating that the reaction rate is directly proportional to the concentration of ChCl₃. Similarly, quadrupling the concentration of ChCl₃ quadruples the reaction rate, further supporting the conclusion that the reaction rate is proportional to the concentration of ChCl₃.