Question

120cm3 of ethane were mixed with 140 cm3 of oxygen and the mixture exploded to complete reaction. Calculate the volume of the resulting gaseous mixture when measured at room temperature and pressure.

Answer 1

The volume of the resulting gaseous mixture when measured at room temperature and pressure is approximately 467 cm3.

Step-by-step explanation:

In order to solve this problem, we need to use the stoichiometry of the reaction between ethane and oxygen. From the balanced equation: 2 CH3CH3 (g) + 7 O2 (g) → 4 CO2 (g) + 6 H2O (g), we can see that for every 2 moles of ethane, 7 moles of oxygen are required.

Since we have 120 cm3 of ethane, we can write the following proportion:

2 moles of ethane / 120 cm3 of ethane = 7 moles of oxygen / x

Solving for x, we find that the volume of oxygen required is approximately 467 cm3.