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A square root function has a domain of x > 2 and a range of y > 5. What is the range of its inverse?

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User Bdanin
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The range of the inverse square root function is x > 2.

We need to analyze the relationship between the domain and range of the original function.

Original Function:

Domain: x > 2 (all values of x greater than 2)

Range: y > 5 (all values of y greater than 5)

Inverse Function:

Domain: y > 5 (all values of y greater than 5)

Range: x > 2 (all values of x greater than 2)

In essence, the domain and range of the original function swap places when finding the inverse.

Therefore, the range of the inverse square root function is x > 2.

User Tobyodavies
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