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An architect is designing a rectangular house that is 60 feet long and 40 feet wide. He uses 1/4 of the area for the living room and 1/5 of the area for the kitchen. What area in square feet is left over for other parts of the house?

User Soredive
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1 Answer

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Final answer:

The total area of the house is 2400 square feet. After subtracting the areas for the living room (600 sq. ft.) and the kitchen (480 sq. ft.), 1320 square feet of area is left for other parts of the house.

Step-by-step explanation:

The problem involves determining the remaining area of a house after allocating parts for the living room and kitchen. To solve this, we calculate the total area of the house, which is the product of its length and width. Then, we compute the areas for the living room and kitchen by applying the respective fractions. Finally, we subtract these areas from the total area to find the remaining space.

The total area is 60 feet x 40 feet = 2400 square feet.

The living room uses 1/4 of the total area, which is 2400 sq. ft. / 4 = 600 sq. ft.,

and the kitchen uses 1/5 of the total area, which is 2400 sq. ft. / 5 = 480 sq. ft..

Thus, the area left for other parts of the house is 2400 sq. ft. - (600 sq. ft. + 480 sq. ft.) = 1320 sq. ft.

User Iuridiniz
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