The centroid of triangle ∆ABC is (18, 12) in coordinate notation. This means that the point of intersection of the medians of the triangle is located at (18, 12).
To find the centroid of a triangle ∆ABC, we need to calculate the average of the x-coordinates and the average of the y-coordinates of its three vertices.
Given the coordinates of points A(4,5), B(20,25), and C(30,6), we can find the centroid as follows:
1. Add the x-coordinates of A, B, and C:
x = 4 + 20 + 30 = 54
2. Divide the sum by 3 to find the average:
x = 54 / 3 = 18
3. Add the y-coordinates of A, B, and C:
y = 5 + 25 + 6 = 36
4. Divide the sum by 3 to find the average:
y = 36 / 3 = 12
Therefore, the centroid of triangle ∆ABC is (18, 12) in coordinate notation. This means that the point of intersection of the medians of the triangle is located at (18, 12).