Question

2Na+ Cl₂ > 2NaCl

2. 23 grams of sodium reacts with chlorine gas. Assuming all of the reactants are used up, how
much chlorine was used if 71 grams of sodium chloride was produced?
A 104 g
C 48 g
D 123 g
B 94 g

Answer 1

To determine how much chlorine was used when 23 grams of sodium react to yield 71 grams of sodium chloride, stoichiometry is applied, revealing that approximately 94 grams of chlorine were consumed in the reaction. The correct answer is option B.

Step-by-step explanation:

To determine the amount of chlorine used when 23 grams of sodium reacts to produce 71 grams of sodium chloride, we'll need to apply stoichiometry based on the balanced chemical equation:

2 Na(s) + Cl₂(g) → 2 NaCl(s)

First, calculate the moles of sodium chloride produced using its molar mass (58.44 g/mol):

(71 g NaCl) ÷ (58.44 g/mol) = 1.215 moles NaCl

Since the stoichiometry of the reaction dictates a 1:1 mole ratio between NaCl and Cl₂, 1.215 moles of Cl₂ were required to produce 1.215 moles of NaCl. To find the mass of chlorine used:

(1.215 moles Cl₂) × (70.90 g/mol) = 86.2155 g Cl₂

The closest answer choice to our calculated mass of 86.2155 grams is 94 grams (Option B). Thus, approximately 94 grams of chlorine were used.