The equation of the line passing through the point (-7, 1) with a slope of -2 is y = -2x - 13.
To find the equation of a line passing through a given point and having a given slope, we can use the point-slope form of a linear equation.
The point-slope form of a linear equation is given by: y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.
In this case, the given point is (-7, 1) and the given slope is -2.
Substituting the values into the point-slope form, we have: y - 1 = -2(x - (-7))
Simplifying the equation, we get: y - 1 = -2(x + 7)
Expanding the equation further, we have: y - 1 = -2x - 14
To isolate y, we can add 1 to both sides of the equation: y = -2x - 13
Therefore, the equation of the line passing through the point (-7, 1) with a slope of -2 is y = -2x - 13.
This equation represents a line in slope-intercept form, where the coefficient of x (-2) represents the slope and the constant term (-13) represents the y-intercept.
The complete question could be
Write an equation of the line with slope of -2 through (7,-1)?