Final answer:
The axis of symmetry of the function f(x) = x^2 - 6x + 8 is x = 3, found using the formula x = -b/2a where a and b are coefficients from the quadratic equation.
Step-by-step explanation:
The axis of symmetry of a quadratic function is a vertical line that divides the graph of the function into two symmetric parts.
To find the axis of symmetry of the function f(x) = x^2 - 6x + 8, we can use the formula x = -b/2a, where a, b, and c are the coefficients of the quadratic function in the form ax^2 + bx + c.
In this case, a = 1, b = -6, and c = 8.
Plugging these values into the formula, we get x = -(-6)/2(1) = 6/2 = 3.
Therefore, the axis of symmetry of the function f(x) = x^2 - 6x + 8 is x = 3.