The system of equation required is :
d = 2c - 5
(c + 3) / (d + 3) = 3/4
b.)
The pet shop couldnt initially have 15 cats and 20 dogs
c.) Number of cats is 9 and number of dogs is 13
A.)
The system of equation which can be used to solve the problem is :
- d = 2c - 5 ___ (1)
- (c + 3) / (d + 3) = 3/4 ___ (2)
b.)
No, the pet shop couldnt initially have 15 cats and 20 dogs because;
c.)
Substituting the value of d in (1) into (2)
(3 + c) / (2c - 5 + 3) = 3/4
cross multiply
3(2c - 2) = 4(3 + c)
6c - 6 = 12 + 4c
6c - 4c = 12 + 6
2c = 18
c = 9
From (1)
d = 2(9) - 5
d = 18 - 5
d = 13