Question

A box contains 3 red, 3 blue, and 4 white balls. In how many ways can 8 balls be drawn out of the box, one at a time, provided order is important?

(a) P(10,8)
(b) P(10,2)
(c) C(10,8)
(d) C(10,2)

Answer 1

The number of ways to draw 8 balls out of the box, one at a time, with order being important, is given by the formula P(n, r) = n! / (n - r)!. In this case, the answer is P(10, 8).

Step-by-step explanation:

In this problem, we need to find the number of ways to draw 8 balls out of the box, one at a time, with order being important. To do this, we use the concept of permutations.

The formula to find the number of permutations of selecting r items from a set of n items is given by P(n, r) = n! / (n - r)!. In this case, we have 10 balls to choose from (3 red, 3 blue, and 4 white) and we want to draw 8 balls. Therefore, the answer is P(10, 8).

The number of ways to draw 8 balls out of the box, one at a time, with order being important, is given by the formula P(n, r) = n! / (n - r)!. In this case, the answer is P(10, 8).