Final answer:
To calculate the approximate number of packets containing two defective bolts in a consignment of 20,000 packets, calculate the probability of getting exactly two defective bolts in a packet and then multiply it by the total number of packets. Round the result to the nearest whole number.
So, the closest option is: A. 8
Step-by-step explanation:
To calculate the approximate number of packets containing two defective bolts in a consignment of 20,000 packets:
- Calculate the probability of getting exactly two defective bolts in a packet. Since the chance of producing a defective bolt is 1/500 and there are 10 bolts in each packet, the probability is given by (1/500)^2 * (499/500)^8 * 10C2, where 10C2 is the combination of 10 bolts taken 2 at a time.
- Calculate the probability of getting two defective bolts in each packet. Since there are 20,000 packets, the probability is given by the product of the probability calculated in step 1 and 20,000.
- Round the result to the nearest whole number to get the approximate number of packets containing two defective bolts.
The approximate number of packets containing two defective bolts in a consignment of 20,000 packets is 3 (option D).