Question

In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600Å, then wavelength of first maximum will be:

A. 3300Å
B. 4400Å
C. 5500Å
D. 6600Å

Answer 1

To find the wavelength of the first maximum, we use the concept of single slit diffraction pattern. The wavelength of the first maximum will be equal to the wavelength of red light, which is 6600Å.

Step-by-step explanation:

To find the wavelength of the first maximum, we need to use the concept of single slit diffraction pattern. In a single slit diffraction pattern, the first minimum occurs at an angle θ given by the equation:

sin(θ) = λ / (2d)

where λ is the wavelength of light and d is the width of the slit.

We are given that the first minimum for red light with a wavelength of 6600Å coincides with the first maximum for some other unknown wavelength. Since the first minimum occurs at the same angle θ for both wavelengths, we can set up the equation:

sin(θ) = λred / (2d) = λmax / (2d)

where λred is the wavelength of red light (6600Å) and λmax is the unknown wavelength of the first maximum. Rearranging the equation, we get:

λmax = λred * (2d) / (2d)

So, the wavelength of the first maximum will be equal to the wavelength of red light, which is 6600Å. Therefore, the answer is D. 6600Å.