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randy is able to choose from two job positions at one company. he has the option to choose the eight hour second shift or the twelve hour day shift, so it is impossible for randy to work the eight hour second shift and the twelve hour day shift. if the probability that randy chooses the eight hour second shift is 0.9, and the probability that randy chooses the twelve hour day shift is 0.03, what is the probability that randy chooses the eight hour second shift or the twelve hour day shift?

User OneGuyInDc
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Final answer:

To find the total probability of Randy choosing either the eight hour second shift or the twelve hour day shift, we add the two given probabilities since the events are mutually exclusive.

The combined probability is 0.9 + 0.03 = 0.93, meaning there is a 93% chance that Randy chooses one of the shifts.

Step-by-step explanation:

The student is asking about calculating the probability that Randy chooses either the eight hour second shift or the twelve hour day shift at his company. According to the problem, Randy has the options to choose either shift, but not both, and the probability for each choice is given.

The probability of choosing the eight hour second shift is 0.9, and the probability of choosing the twelve hour day shift is 0.03.

To find the total probability of choosing either shift, we simply add the individual probabilities because the events are mutually exclusive (Randy can only choose one shift). Therefore:

Probability(Randy chooses one of the shifts) = Probability(eight hour second shift) + Probability(twelve hour day shift) = 0.9 + 0.03 = 0.93.

Hence, there is a 0.93 or 93% chance that Randy chooses either the eight hour second shift or the twelve hour day shift.

User R Esmond
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