Question

a physical pendulum is made of an iron rod of radius 0.500 cm with an iron sphere at the end. the sphere has a radius of 5.00 cm. if the rod is 75.0 cm long, what is the period of oscillation of this pendulum?

Answer 1

To find the period of oscillation of a physical pendulum, we can use the equation: T = 2π√(I/mgh), where T is the period, I is the moment of inertia, m is the mass of the pendulum, g is the acceleration due to gravity, and h is the distance from the pivot point to the center of mass.

Step-by-step explanation:

To find the period of oscillation of a physical pendulum, we can use the equation:

T = 2π√(I/mgh)

where T is the period, I is the moment of inertia, m is the mass of the pendulum, g is the acceleration due to gravity, and h is the distance from the pivot point to the center of mass.

In this case, the length of the rod is given as 75.0 cm. We can find the moment of inertia of the rod using the formula:

I = (1/3)ml²

where l is the length of the rod.

Substituting the given values and solving the equations, we can find the period of oscillation of the pendulum.