a) In order
12KB → 936KB → 42.5MB → 1.14GB → 6.3TB.
bi) 2848 photos.
ii) 28288 more of 1.5MB photo size.
iii) 238 photos of 3.6MB.
iv) I will suggest she uses 2.4MB sized photos.
How the number of photos were calculated.
a) The order from the smallest to largest:Kilobyte (KB) → Megabyte (MB) → Gigabyte (GB) → Terabyte (TB).
so, 12KB → 936KB → 42.5MB → 1.14GB → 6.3TB.
bi) if 1GB can store 178 photos of 4.8 MB
Number of 4.8MB in 16GB = 178 * 16
= 2848 photos.
ii) 1GB stores 572 photos of 1.5MB
64GB will store = 64 * 572 = 36608
1GB stores 130 photos of 6.6MB
64GB will store = 64 * 130 = 8320
The difference = 36608 - 8320
= 28288 more of 1.5MB photo size
c) If 715 photos of 1.2MB can be stored in 1GB
But 3.6MB = 1.2MB * 3
Therefore, approximately the number of 3.6MB that can be stored on 1GB is
= 715/3 = 238 photos of 3.6MB.
iv) To store 13000 photos on 13GB, Sue will has consider this
No of 1.2MB photos = 715 * 32 = 22,880
No of 1.5MB photos = 572 * 32 = 18304
No of 1.8MB photos = 476 * 32 = 15233
No of 2.4MB photos = 357 * 32 = 11424
No of 3.0MB photos = 286 *32 = 9152
No of 4.8MB photos = 178 * 32 = 5696
No of 6.6MB photos = 130 * 32 = 4160
Of all the photo sizes, the number of 2.4MB sized photos that can be stored in 32GB is close to the number she want to store.
Therefore, I will suggest she uses 2.4MB sized photos.