Final answer:
The question involves determining if 172.16.0.16/28 or 192.168.10.64/26 could include the given IP as a usable host address. Both addresses are actually network addresses for their respective subnets, and thus neither can be used as a host address.
Step-by-step explanation:
The question asks which subnet would include the address 172.16.0.16/28 or 192.168.10.64/26 as a usable host address. To determine this, we need to calculate the range of usable IP addresses for each subnet. For the subnet 172.16.0.16/28, the subnet mask is 255.255.255.240, which means we have 16 IP addresses in total but the first address signifies the network and the last address is the broadcast address, leaving 14 addresses for hosts. The IP range for this subnet is 172.16.0.16 to 172.16.0.31, which means 172.16.0.16 is actually the network address and thus not a usable host address.
Looking at the subnet 192.168.10.64/26, the subnet mask is 255.255.255.192, providing 64 IP addresses. The range of this subnet would be 192.168.10.64 to 192.168.10.127, with 192.168.10.65 as the first usable host address and 192.168.10.126 as the last usable host address. Hence, 192.168.10.64 is the network address and not a usable host address as well.
Therefore, neither subnet 172.16.0.16/28 nor 192.168.10.64/26 includes the given addresses as usable host addresses. Both addresses are network addresses, meant to identify the subnet itself rather than any specific device within the subnet.