Question

Determine the percent water in MgSO4*7H20?

Answer 1

`\% H_2O=51.2\%`

Step-by-step explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

`MM_(MgSO_4* 7H_2O)=120.36 g/mol+7*18.02g/mol\\\\MM_(MgSO_4* 7H_2O)=246.5g/mol`

Thus, the percent water is:

`\% H_2O=(7*MM_(H_2O))/(MM_(MgSO_4* 7H_2O)) *100\%\\\\`

So we plug in to obtain:

`\% H_2O=(7*18.02)/(246.5) *100\%\\\\\% H_2O=51.2\%`

Best regards!