Question

A gas in a piston starts out with a volume of 156 mL, a temperature of 28.1° C, and a pressure of 1.12 atm. If it ends with a volume of 312 mL and a temperature of 87.2° C, what is the new pressure?

Answer 1

0.67atm is the new pressure of the gas

Step-by-step explanation:

To find one condition of a gas when pressure, volume and absolute temperature change we must use combined gas law:

`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

Where P is pressure, V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.

Replacing:

P₁ = 1.12atm

V₁ = 156mL

T₁ = 28.1°C + 273.15K = 301.25K

P₂ = ?

V₂ = 312mL

T₂ = 87.2°C + 273.15 = 360.35K

1.12atm*156mL / 301.25K = P₂*312mL / 360.35K

P₂ = 0.67atm is the new pressure of the gas