Question

On a coordinate plane, if you take a point from (2, -5) and move it up 3 units to point "A" what is the distance of point a to coordinates (5, 0)?

A. 3
B. Square root of 11
C. Square root of 13
D. 5

Answer 1

First we need to find the point after the translation of 3 units up.

(2,-5)->(2,-2)

Now we have the point (2,-2) we just need to use the difference formula to find the distance between this point and (5,0)

Distance=
`√((5-2)^2+(0-(-2))^2)`

Now we need to simplify/solve this expression

=
`√(3^2+2^2)`

=
`\sqrt13`

Therefore the answer is C!

Answer 2

C

Explanation:

(2,-5) move up three steps is (2, -2). if you draw it on a paper(and draw lines to connect them), you can see that they form a right triangle. apply a²+b²=c² and you should get 3²+2²=(√13)²