Question

Log(2)10 = log(2)2 +_____

Answer 1

Given:

`\log_210=\log_22+___`

To find:

The missing value.

Solution:

Let the missing value be x. Then

`\log_210=\log_22+x`

`\log_210-\log_22=x`

Using property of logarithm, we get

`\log_2\left((10)/(2)\right)=x`
`[\because \log (a)/(b)=\log a - \log b]`

`\log_2\left(5\right)=x`

Therefore, the missing value is
`\log_2\left(5\right)`.