Final Answer:
The pair of numbers with the maximum product is (c) 130, 120. Their product is 15,600, exceeding the other options.
Step-by-step explanation:
Let x be the first number and y be the second number. We have two equations:
x + 9y = 1419 (sum constraint)
P = xy (product to maximize)
We want to maximize P subject to the constraint in equation 1. Using
Lagrange multipliers, we set up the following equation:
L(x, y, λ) = xy - λ(x + 9y - 1419)
Taking partial derivatives and setting them equal to zero:
∂L/∂x = y - λ = 0
∂L/∂y = x - 9λ = 0
∂L/∂λ = -x - 9y + 1419 = 0
Solving this system of equations, we get x = 130 and y = 120. Checking the other options, we find their products to be:
(a) 100 * 150 = 15,000
(b) 120 * 130 = 15,600 (matches our maximum)
(d) 150 * 100 = 15,000
Therefore, (c) 130, 120 has the highest product of 15,600, making it the optimal solution.