Question

Consider Model 2. Verify that diluting 10 mL of a 0.60 M copper(II) sulfate solution to 100 mL will produce a 0.060 M solution. Identify m1, v1, and v2, and calculate m2.

a) m1 = 0.60 M, v1 = 10 mL, v2 = 100 mL, m2 = 0.060 M
b) m1 = 0.060 M, v1 = 10 mL, v2 = 100 mL, m2 = 0.60 M
c) m1 = 0.60 M, v1 = 100 mL, v2 = 10 mL, m2 = 0.060 M
d) m1 = 0.060 M, v1 = 100 mL, v2 = 10 mL, m2 = 0.60 M

Answer 1

a) m1 = 0.60 M, v1 = 10 mL, v2 = 100 mL, m2 = 0.060 M.To verify the dilution, the dilution equation M1 × V1 = M2 × V2 is used. With an initial molarity (m1) of 0.60 M, initial volume (v1) of 10 mL,

Step-by-step explanation:

To verify if diluting 10 mL of a 0.60 M copper(II) sulfate solution to 100 mL will produce a 0.060 M solution, we use the dilution equation: M1 × V1 = M2 × V2. Here, M1 is the initial molarity, V1 is the initial volume of the solution before dilution, M2 is the molarity after dilution, and V2 is the final volume after dilution.

Using the given values, m1 = 0.60 M (initial molarity), v1 = 10 mL (initial volume), and v2 = 100 mL (final volume). We can calculate M2 (final molarity) by rearranging the equation to M2 = (M1 × V1) / V2. Plugging in our values, we get M2 = (0.60 M × 10 mL) / 100 mL = 0.060 M. Therefore, m2 = 0.060 M (final molarity). The correct option is (a).