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At a certain temperature, the solubility of nitrogen gas in water is 6.8x10 to the -4 M at a partial pressure of 1.5 atm. Calculate the solubility of nitrogen gas in water when the partial pressure is increased to 3.0 atm at the same temperature

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Answer: The solubility of a gas in a liquid is directly proportional to its partial pressure. In this case, we need to calculate the solubility of nitrogen gas in water when the partial pressure is increased from 1.5 atm to 3.0 atm, while keeping the temperature constant.

Step-by-step explanation:

To solve this problem, we can use the following formula:

C2 = C1 * (P2 / P1)

Where:

C1 is the initial solubility of nitrogen gas in water (6.8x10^-4 M)

P1 is the initial partial pressure of nitrogen gas (1.5 atm)

P2 is the final partial pressure of nitrogen gas (3.0 atm)

C2 is the final solubility of nitrogen gas in water (the value we need to find)

Substituting the given values into the formula:

C2 = (6.8x10^-4 M) * (3.0 atm / 1.5 atm)

C2 = 13.6x10^-4 M

Therefore, the solubility of nitrogen gas in water when the partial pressure is increased to 3.0 atm is 13.6x10^-4 M.

Please note that the solubility is directly proportional to the partial pressure, so doubling the pressure doubles the solubility.

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