Question

Consider the following method.

public static int mystery(String string1, String string2)
{
String temp = string1;
int position = 0;
int result = 0;
while(temp.indexOf(string2) >= 0)
{
position = temp.indexOf(string2);
result++;
temp = temp.substring(position + 1);
}
return result;
}
The following code segment appears in another method in the same class.
System.out.println(mystery("Mississippi", "si"));
What, if anything, is printed as a result of executing the code segment?
A 0
B 1
C 2
D 3
E Nothing is printed.

Answer 1

The code segment will print the number 2 as a result of executing the code.

Step-by-step explanation:

The code segment mystery("Mississippi", "si") will print the number 2 as a result of executing the code. The mystery method counts how many times the second string occurs inside the first string by using a while loop and the indexOf method. In this case, the second string is "si" and it occurs twice in the string "Mississippi", so the output will be 2.