Question

In the context of the byte rotation scheme for the mov instruction, which of the following is the correct instruction to load the constant 0x17400 into register r6?

a) mov r6, #0x17400
b) mov r6, #0x174
c) mov r6, #0x40017
d) mov r6, #0x400

Answer 1

The correct mov instruction to load the constant 0x17400 into register r6, assuming a byte rotation encoding scheme, is likely 'mov r6, #0x174'. This accounts for architectures that use bit rotation to encode immediate values for the mov instruction. a) mov r6, #0x17400 is the correct answer.

Step-by-step explanation:

The instruction to load the constant 0x17400 into register r6 in the context of the byte rotation scheme for the mov instruction would depend on the specific architecture and instruction set of the processor being used.

However, assuming that the architecture uses a form of rotation that allows an immediate value to be rotated into the correct position, the likely correct instruction would be mov r6, #0x174.

This is because, in some architectures like ARM, immediate values for the mov instruction are actually encoded through bit rotation and can require encoding a rotated value that the processor will rotate back during execution to get the original value.

So if the architecture rotates the 8 least significant bits of the immediate value by two bit positions to the left when it decodes the instruction, then mov r6, #0x174 would result in r6 containing the value 0x17400 after the instruction is executed.