Final answer:
The energy of a photon with a frequency of 1.0×10^15 Hz, using Planck’s constant (6.626 × 10^-34 J·s), is calculated as 6.626 × 10^-19 J. Multiplying Planck's constant by six is not relevant to the calculation and would lead to an incorrect value.
Step-by-step explanation:
To calculate the energy of a photon with a given frequency when Planck’s constant is known, we use the formula E = hf, where E represents the energy in joules (J), h is Planck’s constant, and f is the frequency of the photon in hertz (Hz), which is equivalent to 1/s.
Given the frequency of a photon is 1.0×1015 Hz, and knowing that Planck’s constant is 6.626 × 10-34 J·s, we can substitute these values into the formula to find the energy:
E = (6.626 × 10-34 J·s)(1.0×1015 Hz)
= 6.626 × 10-19 J.
If Planck's constant is multiplied by six, as implied by the question, it would result in an incorrect value for energy calculations in the context of photon energy, because Planck's constant is a defined physical constant and should not be arbitrarily multiplied.