Question

In the circuit below, what is the current measured by the ammeter? Each resistor is 10 ohms, and the battery is 10 volts.

A. 0.5 A.
B. 1 A.
C. 2 A.
D. 5 A.

Answer 1

The current measured by the ammeter in the circuit is 1 A (B).

Step-by-step explanation:

In this circuit, the total resistance can be found by calculating the equivalent resistance of the series circuit. As all resistors are of the same value (10 ohms each), the total resistance (R_total) can be calculated by adding these resistances together: R_total = R1 + R2 + R3 = 10 ohms + 10 ohms + 10 ohms = 30 ohms.

Using Ohm's Law (V = IR), where V is the voltage (10 volts) and R is the resistance (30 ohms), we can find the total current (I_total) flowing through the circuit: I_total = V / R_total = 10 volts / 30 ohms = 1/3 A.

Now, according to Kirchhoff's junction rule, in a series circuit, the current remains constant throughout the circuit. Therefore, the current measured by the ammeter (which is connected in series) is the same as the total current. Thus, the current measured by the ammeter is also 1 A (B), as it matches the total current flowing through the circuit.

The answer, therefore, is 1 A (B), as the total current passing through the circuit and the current measured by the ammeter are both 1 ampere due to the properties of a series circuit.