Question

Consider int count; If we pass &count as a parameter then, within the called function, we can set count to 5 by using:

A) count = 5;
B) count = 5;
C) &count = 5;
D) (&count) = 5;

Answer 1

To set the value of 'count' to 5 by passing its address, '&count', to a function, you should use '*pointer = 5;' where 'pointer' is the parameter in the function that holds the address of 'count'.

Step-by-step explanation:

If &count is passed as a parameter to a function, the correct way to set the value of count to 5 within the called function is by using the *pointer notation. Since &count is an address of the variable count, within the function, you'd have a pointer variable that you can dereference to access count's value and change it. The correct statement to set count to 5 is option A) *pointer = 5; where pointer is the name of the parameter accepting the address.

To clarify, if count is an integer and you are passing its address to a function, inside that function you should have a parameter that is a pointer to an integer, commonly declared as int* ptr or similar. Then, by doing *ptr = 5;, you directly modify the value of count since ptr holds the address of count and *ptr allows you to access and change the value stored at that address.