Question

Suppose we write lists by listing the values of the elements between curly braces (note: code below was corrected after the due date to show curly braces). For example, the list {1, 3, 5, 7} represents a List of Integers, containing the first four odd numbers.

Let odd = {1, 3, 5, 7} and even = {8, 6, 4, 2}.
Assume each of the following happens in sequence, that is, if odd is modified in one question, carry that value forward into the next question.
What is the contents of odd if we call odd.addAll(even)?

Answer 1

When the operation odd.addAll(even) is performed, the list 'odd' combines with the list 'even' in sequence, resulting in the list odd being {1, 3, 5, 7, 8, 6, 4, 2}.

Step-by-step explanation:

The contents of odd after calling odd.addAll(even) would be {1, 3, 5, 7, 8, 6, 4, 2}. When we call the addAll() method on the odd list and pass in the even list, it appends all the elements from even to the end of odd. In this case, it appends {8, 6, 4, 2} to the end of {1, 3, 5, 7}. Therefore, the new contents of odd are {1, 3, 5, 7, 8, 6, 4, 2}.

According to the scenario provided, if we have two lists named odd and even, where odd = {1, 3, 5, 7} and even = {8, 6, 4, 2}, and we perform the operation odd.addAll(even), we are essentially combining both lists. This operation will append the elements of the even list to the end of the odd list.

After performing this operation, the contents of the odd list will be updated to include the elements of the even list. Therefore, the list odd would then contain the following integers in this order: {1, 3, 5, 7, 8, 6, 4, 2}. The elements are added in the sequence that they appear in the even list.