Question

What is output when ch stores the value 'b'?

switch (ch) {
case 'a':
case 'A': cout << "Option A ";
break;
case 'b':
case 'B': cout << "Option B ";
break;
case 'c':
case 'C': cout << "Option C ";
break;
default: cout << "Invalid choice";
}

Answer 1

If ch stores 'b', the output of the switch-case statement is "Option B ". This is because the case for 'b' and 'B' in the switch-case statement have the same output string without a preceding break statement, showcasing the ability to handle both cases identically.

Step-by-step explanation:

When ch stores the value 'b', the output will be "Option B ".

The provided code is an example of a switch-case statement in C++. When the variable ch has the value 'b', the control flows to the matching case label, outputting the associated message without a break statement in the preceding case, as it does not exist. Case labels 'b' and 'B' share the same output instruction, ensuring that either lowercase or uppercase 'b' will result in the same output.

This demonstrates how switch-case statements can be designed to handle multiple cases with the same response, effectively grouping 'b' and 'B' together.The output when ch stores the value 'b' will be Option B.Explanation: The switch statement evaluates the value of the variable ch and checks it against each case. Since the value of ch is 'b', it matches the 'b' case in the switch statement, and the code block for that case is executed. This code block prints 'Option B' to the console.