Question

A hurdler is 0.635 m from a hurdle when he jumps at 3.22 m/s at a 62.9 degrees angle. How many seconds later does he clear the hurdle? (Hint: it is not necessarily at the highest point in his motion.) (Unit = s) Watch sig figs.

Answer 1

Step-by-step explanation:

The horizontal distance of the hurdle = .635 m

This distance is covered by hurdler by horizontal component of his velocity

horizontal component of hurdler's initial velocity = 3.22 x cos 62.9

= 1.4668 m /s

displacement in horizontal direction = .635 m , acceleration = 0 as no force acts in horizontal direction .

So time taken to clear the hurdle

= .635 / 1.4668 s

= .433 s .