Final answer:
The number of moles of Ca(NO3)2 in 23.25 g is calculated using the molar mass of calcium nitrate (164.10 g/mol) and the formula for moles, resulting in 0.1416 moles.
Step-by-step explanation:
To find out how many moles would be found in 23.25 g of Ca(NO3)2, we first need to calculate the molar mass of calcium nitrate, Ca(NO3)2. Using atomic masses from the periodic table:
- Calcium (Ca) = 1x 40.078 g/mol
- Nitrogen (N) = 2x 14.007 g/mol
- Oxygen (O) = 6x 15.999 g/mol
Adding these molar masses gives us:
40.078 g/mol (Ca) + 2x 14.007 g/mol (N) + 6x 15.999 g/mol (O) = 164.10 g/mol for Ca(NO3)2.
Next, to find the number of moles of Ca(NO3)2 in 23.25 g, we use the formula:
moles = mass (g) / molar mass (g/mol)
moles = 23.25 g / 164.10 g/mol = 0.1416 moles of Ca(NO3)2