Question

The pressure inside a commercial airliner is maintained at 1 ATM (105 N/m²). What is the outward force exerted on a 1m×2m cabin door if the outside pressure (at 10 km height) is 0.3 ATM?

Answer 1

The outward force exerted on the cabin door is 6 × 10^4 N.

Step-by-step explanation:

The outward force exerted on a 1m×2m cabin door can be calculated using the concept of pressure.

The pressure inside the airliner is 1 ATM, which is equivalent to 1.01 × 10^5 N/m².

The outside pressure at a height of 10 km is 0.3 ATM, which is equivalent to 3 × 10^4 N/m².

To find the outward force, we can use the formula:

Force = Pressure × Area

Substituting the values:

Force = (3 × 10^4 N/m²) × (1m × 2m)

= 6 × 10^4 N

Therefore, the outward force exerted on the cabin door is 6 × 10^4 N.